[ee122] hmwk problem Number 2.16

[Jonathan D. Ellithorpe]

I think the MTU is actually defined as being the maximum amount of data 
that a link layer frame can encapsulate. Thus, we don't need to consider 
the size of the frame, since we're just given the MTU of the link-layer.


Jorge Ortiz wrote:
> On 9/20/07, Nescio Nomen <nescionomen at gmail.com> wrote:
>   
>> For hmwk Problem #2, P16, do we know if the datagram will have a TCP header
>> inside?  (Is it necessarily the case that a datagram always encapsulated a
>> TCP header?)
>>     
>
> If it's specified as only being a plane datagram (as it is in the
> problem), we only need to include the IP header.
>
>   
>> Also, when we are transmitting into the link, how big is the
>> frame header?
>>     
>
> Treat the packet as having only an IP header and the data you wish to send.
>
>   
>> We haven't really talked about this layer yet.  Does the size
>> of the frame header depend on the technology, i.e. optical?
>>     
>
> It may, yes.  Different mediums may have different header definitions.
>
> jorge
>
>   
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