[ee122] hmwk problem Number 2.16

Jorge Ortiz jortiz at cs.berkeley.edu
Thu Sep 20 17:43:44 PDT 2007


Yes, but you do have to account for the amount of data that you're
sending per packet.  This is a function of the header size.  The
larger your header, the less data you send per packet, the more
packets you have to send to get all your data through.

jorge


On 9/20/07, Jonathan D. Ellithorpe <jde at berkeley.edu> wrote:
> I think the MTU is actually defined as being the maximum amount of data
> that a link layer frame can encapsulate. Thus, we don't need to consider
> the size of the frame, since we're just given the MTU of the link-layer.
>
>
> Jorge Ortiz wrote:
> > On 9/20/07, Nescio Nomen <nescionomen at gmail.com> wrote:
> >
> >> For hmwk Problem #2, P16, do we know if the datagram will have a TCP header
> >> inside?  (Is it necessarily the case that a datagram always encapsulated a
> >> TCP header?)
> >>
> >
> > If it's specified as only being a plane datagram (as it is in the
> > problem), we only need to include the IP header.
> >
> >
> >> Also, when we are transmitting into the link, how big is the
> >> frame header?
> >>
> >
> > Treat the packet as having only an IP header and the data you wish to send.
> >
> >
> >> We haven't really talked about this layer yet.  Does the size
> >> of the frame header depend on the technology, i.e. optical?
> >>
> >
> > It may, yes.  Different mediums may have different header definitions.
> >
> > jorge
> >
> >
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