[ee122] hmwk problem Number 2.16

[Jorge Ortiz]

The MTU is the largest sized packet that can be passed.  This includes
header information.


On 9/20/07, Nescio Nomen <nescionomen at gmail.com> wrote:
> Oh wait, I think I understand-- you're saying that MTU does not include the
> link header size?
>
>
> On 9/20/07, Nescio Nomen < nescionomen at gmail.com> wrote:
> > I'm not sure I understand.  (in a real life problem) why wouldn't we need
> to know the size of the frame header just because we are given the MTU?
> Wouldn't we try to find the amount of 'real data' that could fit by doing
> something along the lines of MTU - frame header size - IP header size -
> Layer 4 header size?
> >
> >
> >
> > On 9/20/07, Jonathan D. Ellithorpe < jde at berkeley.edu> wrote:
> > > I think the MTU is actually defined as being the maximum amount of data
> > > that a link layer frame can encapsulate. Thus, we don't need to consider
> > > the size of the frame, since we're just given the MTU of the link-layer.
> > >
> > >
> > > Jorge Ortiz wrote:
> > > > On 9/20/07, Nescio Nomen <nescionomen at gmail.com> wrote:
> > > >
> > > >> For hmwk Problem #2, P16, do we know if the datagram will have a TCP
> header
> > > >> inside?  (Is it necessarily the case that a datagram always
> encapsulated a
> > > >> TCP header?)
> > > >>
> > > >
> > > > If it's specified as only being a plane datagram (as it is in the
> > > > problem), we only need to include the IP header.
> > > >
> > > >
> > > >> Also, when we are transmitting into the link, how big is the
> > > >> frame header?
> > > >>
> > > >
> > > > Treat the packet as having only an IP header and the data you wish to
> send.
> > > >
> > > >
> > > >> We haven't really talked about this layer yet.  Does the size
> > > >> of the frame header depend on the technology, i.e. optical?
> > > >>
> > > >
> > > > It may, yes.  Different mediums may have different header definitions.
> > > >
> > > > jorge
> > > >
> > > >
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